A) 2-butene
B) 2-butyne
C) 2-butanol
D) Butanal
Correct Answer: A
Solution :
\[\underset{\text{2-butene}}{\mathop{\underset{\text{(Cis)}}{\mathop{\underset{C{{H}_{3}}}{\mathop{\underset{|\,\,\,\,\,}{\mathop{HC}}\,}}\,=\underset{C{{H}_{3}}}{\mathop{\underset{|\,\,\,\,\,}{\mathop{CH}}\,}}\,}}\,}}\,\] and \[\underset{\text{2-butene}}{\mathop{\underset{\text{(Trans)}}{\mathop{\underset{C{{H}_{3}}}{\mathop{\underset{\,|\,\,\,\,\,\,\,}{\mathop{HC\,}}\,}}\,=\overset{\,C{{H}_{3}}}{\mathop{\overset{|\,\,\,\,\,}{\mathop{CH}}\,}}\,}}\,}}\,\]
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