A) 1-butanol
B) 2-butanol
C) 3-butanol
D) 4-heptanol
Correct Answer: B
Solution :
2-butanol \[(C{{H}_{3}}-\underset{OH}{\mathop{\underset{|\,\,\,\,\,\,}{\mathop{CH}}\,}}\,-C{{H}_{2}}-C{{H}_{3}})\] is optically active because it has asymmetric carbon atom.
You need to login to perform this action.
You will be redirected in
3 sec
