A) \[e+1\]
B) \[e-1\]
C) \[1-e\]
D) \[e\]
Correct Answer: B
Solution :
\[\underset{n\to \infty }{\mathop{\lim }}\,\sum\limits_{r=1}^{n}{\frac{1}{n}{{e}^{\frac{r}{n}}}=\int_{0}^{1}{{{e}^{x}}dx=[{{e}^{x}}]_{0}^{1}=e-1}}\].
You need to login to perform this action.
You will be redirected in
3 sec
