JEE Main & Advanced Mathematics Definite Integration Question Bank Summation of series by Definite Integration, Gamma function, Leibnitz's rule

  • question_answer
    If \[\varphi (x)=\int_{1/x}^{\sqrt{x}}{\sin ({{t}^{2}})\,dt,}\] then \[{\varphi }'(1)=\]

    A)                 \[\sin 1\]             

    B)                 \[2\sin 1\]

    C)                 \[\frac{3}{2}\sin 1\]        

    D)                 None of these

    Correct Answer: C

    Solution :

                       \[\varphi '(x)=\sin x\frac{d}{dx}\sqrt{x}-\sin \frac{1}{{{x}^{2}}}\frac{d}{dx}\left( \frac{1}{x} \right)\]                            \[=\sin x.\frac{1}{2\sqrt{x}}+\frac{1}{{{x}^{2}}}\sin \frac{1}{{{x}^{2}}}\]                                 Þ \[\varphi '(1)=\frac{1}{2}\sin 1+\sin 1=\frac{3}{2}\sin 1\].


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