A) \[(2,\,\,2)\]
B) No value of \[x\]
C) \[(0,\,\,\infty )\]
D) \[(-\infty ,\,\,0)\]
Correct Answer: D
Solution :
\[f'(x)={{e}^{-{{({{x}^{2}}+1)}^{2}}}}.2x-{{e}^{-{{({{x}^{2}})}^{2}}}}.2x=2x{{e}^{-({{x}^{4}}+1+2{{x}^{2}})}}\left( 1-{{e}^{2{{x}^{2}}+1}} \right)\] Þ \[f'(x)>0,\forall x\in (-\infty ,0).\]You need to login to perform this action.
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