JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Superposition of S H M and Resonance

  • question_answer
    A particle with restoring force proportional to displacement and resisting force proportional to velocity is subjected to a force \[F\sin \omega t\]. If the amplitude of the particle is maximum for \[\omega ={{\omega }_{1}}\] and the energy of the particle is maximum for \[\omega ={{\omega }_{2}}\], then (where w0 natural frequency of oscillation of particle)                                                                      [CBSE PMT 1998]

    A)            \[{{\omega }_{1}}={{\omega }_{0}}\] and \[{{\omega }_{2}}\ne {{\omega }_{o}}\]

    B)            \[{{\omega }_{1}}={{\omega }_{0}}\] and \[{{\omega }_{2}}={{\omega }_{o}}\]

    C)            \[{{\omega }_{1}}\ne {{\omega }_{0}}\] and \[{{\omega }_{2}}={{\omega }_{o}}\]

    D)            \[{{\omega }_{1}}\ne {{\omega }_{0}}\] and \[{{\omega }_{2}}\ne {{\omega }_{o}}\]

    Correct Answer: C

    Solution :

               Energy of particle is maximum at resonant frequency i.e., \[{{\omega }_{2}}={{\omega }_{o}}\]. For amplitude resonance (amplitude maximum) frequency of driver force \[\omega =\sqrt{\omega _{o}^{2}-{{b}^{2}}2{{m}^{2}}}\] Þ \[{{\omega }_{1}}\ne {{\omega }_{o}}\]


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