A) \[7:9\]
B) \[49:81\]
C) \[9:7\]
D) \[27:23\]
Correct Answer: A
Solution :
(a): Let the side of the cube be = a units Total surface area of 3 cubes \[=3\times 6{{a}^{2}}\] \[=18\,\,{{a}^{2}}\] Total surface area of cuboid \[=18\,\,{{a}^{2}}-4{{a}^{2}}=14{{a}^{2}}\] \[\therefore \] Ratio\[=\frac{14{{a}^{2}}}{18{{a}^{2}}}=7:9\]You need to login to perform this action.
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