A) \[\text{25}.0\text{25 c}{{\text{m}}^{\text{3}}}\]
B) \[\text{2}.\text{5}0\text{25 c}{{\text{m}}^{\text{3}}}\]
C) \[\text{25}0\text{2}.\text{5 c}{{\text{m}}^{\text{3}}}\]
D) \[\text{25}0.\text{25 c}{{\text{m}}^{\text{3}}}\]
Correct Answer: D
Solution :
\[TSA=2\pi r(r+h)\] \[220=2\times \frac{22}{7}\times r\left( r+\frac{13}{2} \right)\] \[\Rightarrow \] \[r=-10,\frac{7}{2}\] Since radius cannot be ? ve, \[\therefore \]\[r=\frac{7}{2}\] \[\therefore \]\[V=\pi {{r}^{2}}h=250.25\,c{{m}^{3}}\] Hence, volume of the cylinder \[=\text{25}0.\text{25 c}{{\text{m}}^{\text{3}}}\]
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