A) \[42.15\,c{{m}^{3}}\]
B) \[41.52\,c{{m}^{3}}\]
C) \[41.25\,c{{m}^{3}}\]
D) \[40\,c{{m}^{3}}\]
Correct Answer: C
Solution :
Let r and R be inner and outer radius of bowl respectively. Then, \[r=5\text{ }cm,\text{ }R=5+0.25=5.25\text{ }cm.\] Volume of steel used = Outer volume - Inner volume \[=\frac{2}{3}\pi {{(5.25)}^{3}}-\frac{2\pi }{3}{{(5)}^{3}}=41.25c{{m}^{3}}\]You need to login to perform this action.
You will be redirected in
3 sec