A) 50%
B) 75%
C) 100%
D) 125%
Correct Answer: D
Solution :
The edges of cube is ?a? units. The edge is increased by 50% \[=a+\frac{a}{2}=\frac{3a}{2}\] \[\therefore \]Surface area \[=6{{a}^{2}}=\frac{27{{a}^{2}}}{2}\] \[\therefore \]Percentage increase of surface area \[=\frac{\left( \frac{27{{a}^{2}}}{2}-6{{a}^{2}} \right)}{6{{a}^{2}}}\times 100%=125%\]You need to login to perform this action.
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