A) \[g=ab\]
B) \[{{g}^{2}}={{a}^{2}}+{{b}^{2}}\]
C) \[{{g}^{2}}=ab\]
D) \[g=a+b\]
Correct Answer: D
Solution :
According to the condition, \[\sqrt{{{(g-0)}^{2}}+{{(0-0)}^{2}}}=a+b\Rightarrow g=a+b\].You need to login to perform this action.
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