A) \[{{x}^{2}}+{{y}^{2}}-4x-4y-3=0\]
B) \[3({{x}^{2}}+{{y}^{2}})+4x-4y-3=0\]
C) \[{{x}^{2}}+{{y}^{2}}+4x+4y-3=0\]
D) \[3({{x}^{2}}+{{y}^{2}})+4(x+y)-3=0\]
Correct Answer: D
Solution :
Let circle be\[{{x}^{2}}+{{y}^{2}}+2gx+2fy+c=0\]. Then according to the conditions given, \[g+2f=c+3\] ?. (i) \[2g+4f=c+5\] ?. (ii) \[-7g-8f=c-9\] ?. (iii) \[\Rightarrow g=\frac{2}{3},\ f=\frac{2}{3},\ c=-1\] Therefore, the required equation is \[3({{x}^{2}}+{{y}^{2}})+4(x+y)-3=0\].You need to login to perform this action.
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