JEE Main & Advanced Mathematics Circle and System of Circles Question Bank System of circles

  • question_answer
    Two given circles \[{{x}^{2}}+{{y}^{2}}+ax+by+c=0\]and \[{{x}^{2}}+{{y}^{2}}+dx+ey+f=0\]will intersect each other orthogonally, only when                   

    A)            \[a+b+c=d+e+f\]                 

    B)            \[ad+be=c+f\]

    C)            \[ad+be=2c+2f\]                   

    D)            \[2ad+2be=c+f\]

    Correct Answer: C

    Solution :

               From Condition for orthogonal intersection, \[\frac{ad}{2}+\frac{be}{2}=c+f\]


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