A) \[23{{x}^{2}}+23{{y}^{2}}-156x+38y+168=0\]
B) \[23{{x}^{2}}+23{{y}^{2}}+156x+38y+168=0\]
C) \[{{x}^{2}}+{{y}^{2}}+156x+38y+168=0\]
D) None of these
Correct Answer: A
Solution :
Equation of circle is \[({{x}^{2}}+{{y}^{2}}-8x-2y+7)+\lambda ({{x}^{2}}+{{y}^{2}}-4x+10y+8)=0\] Also point \[(3,\ -3)\] lies on the above equation. \[\Rightarrow \lambda =\frac{7}{16}\] Hence required equation is \[23{{x}^{2}}+23{{y}^{2}}-156x+38y+168=0\].
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