A) 2
B) - 2
C) - 1
D) None of these
Correct Answer: C
Solution :
Given circle is \[{{x}^{2}}+{{y}^{2}}=1\] \[C(0,0)\] and radius = 1 and chord is \[y=mx+1\] \[\cos {{45}^{o}}=\frac{CP}{CR}\] \[CP=\]Perpendicular distance from (0,0) to chord \[y=mx+1\] \[CP=\]\[\frac{1}{\sqrt{{{m}^{2}}+1}}\] (CR = radius = 1) \[\cos 45{}^\circ =\frac{1/\sqrt{{{m}^{2}}+1}}{1}\Rightarrow \frac{1}{\sqrt{2}}=\frac{1}{\sqrt{{{m}^{2}}+1}}\] \[{{m}^{2}}+1=2\] Þ \[m=\pm 1.\]You need to login to perform this action.
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