A) (3, 2)
B) (1, 2)
C) (2, 3)
D) (0, 2)
Correct Answer: A
Solution :
Let circle \[{{x}^{2}}+{{y}^{2}}+2gx+2fy+c=0\] .....(i) Circle (i) cuts orthogonally each of the given three circles. Then according to the condition \[2{{g}_{1}}{{g}_{2}}+2{{f}_{1}}{{f}_{2}}={{c}_{1}}+{{c}_{2}}\], \[2g+17f=c+4\] .....(ii) \[7g+6f=c+11\] .....(iii) \[-g+22f=c+3\] .....(iv) From (ii), (iii) and (iv), \[g=-3,\,\]\[f=-2\] Therefore, the centre of the circle \[(-g,\,-f)=\,(3,\,2)\].You need to login to perform this action.
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