JEE Main & Advanced Mathematics Circle and System of Circles Question Bank System of circles

  • question_answer
    If the circles \[{{x}^{2}}+{{y}^{2}}=4,{{x}^{2}}+{{y}^{2}}-10x+\lambda =0\] touch externally, then \[\lambda \]is equal to                               [AMU 1999]

    A)            -16 

    B)            9

    C)            16  

    D)            25

    Correct Answer: A

    Solution :

               Circles x2 + y2 = 4, x2 + y2 ? 10x + l = 0 touch externally                    \ \[{{C}_{1}}{{C}_{2}}={{r}_{1}}+{{r}_{2}}\]                    Þ \[{{C}_{1}}(0,\,0)\] and  \[{{C}_{2}}=(5,\,0)\]                    \[{{r}_{1}}=2\] and \[{{r}_{2}}=\sqrt{25+\lambda }\]                    \ \[\sqrt{{{(5-0)}^{2}}+0}=2+\sqrt{25+\lambda }\]                          Þ   \[5-2=\sqrt{25+\lambda }\] Þ \[3=\sqrt{25+\lambda }\]                    Þ  \[9=25+\lambda \] Þ l = ? 16.


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