JEE Main & Advanced Mathematics Circle and System of Circles Question Bank System of circles

  • question_answer
    The equation of radical axis of the circles \[{{x}^{2}}+{{y}^{2}}+x-y+2=0\] and \[3{{x}^{2}}+3{{y}^{2}}-4x-12=0,\]is  [RPET 1984, 85, 86, 91, 2000]

    A)            \[2{{x}^{2}}+2{{y}^{2}}-5x+y-14=0\]

    B)            \[7x-3y+18=0\]

    C)            \[5x-y+14=0\]

    D)            None of these

    Correct Answer: B

    Solution :

               Radical axis is \[{{S}_{1}}-{{S}_{2}}\]                    \[{{S}_{1}}\equiv {{x}^{2}}+{{y}^{2}}+x-y+2=0\]                    \[{{S}_{2}}={{x}^{2}}+{{y}^{2}}-\frac{4}{3}x-4=0\]                    \[\Rightarrow {{S}_{1}}-{{S}_{2}}=\frac{7}{3}x-y+6=0\]                    or \[7x-3y+18=0\].


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