A) \[2x+y=3\]
B) \[x-2y=3\]
C) \[x+2y=3\]
D) None of these
Correct Answer: C
Solution :
The equation of tangent to the given circle at \[(1,\,1)\] is \[2x+2y-(x+1)-\]\[\frac{5}{2}\,(y+1)+3=0\] \[\Rightarrow \] \[x-\frac{1}{2}\,y-\frac{1}{2}=0\] \[\Rightarrow \]\[2x-y-1=0\] Slope of tangent = 2, \[\therefore \] Slope of normal \[=-\frac{1}{2}\] Hence equation of normal at (1, 1) is \[y-1=-\frac{1}{2}(x-1)\] \[\Rightarrow \] \[x+2y=3.\]
You need to login to perform this action.
You will be redirected in
3 sec
