A) 5, -35
B) -5, 35
C) 7, -32
D) -7, 32
E) 3, -13
Correct Answer: A
Solution :
Equation of circle is, \[{{x}^{2}}+{{y}^{2}}-2x+6y-6=0\] \[{{(x-1)}^{2}}+{{(y+3)}^{2}}={{(4)}^{2}}\] Radius of circle = 4 And centre of circle \[=(1,-3)\] Equation of tangent \[3x-4y+k=0\] \ \[\frac{3\times 1-4\times (-3)+k=0}{\sqrt{{{(3)}^{2}}+{{(-4)}^{2}}}}=\pm 4\]. Hence, \[k=5,-35\].
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