JEE Main & Advanced Mathematics Circle and System of Circles Question Bank Tangent and normal to a circle

  • question_answer
    If the line \[lx+my+n=0\]be a tangent to the circle \[{{(x-h)}^{2}}+{{(y-k)}^{2}}={{a}^{2}},\]then

    A)            \[hl+km+n={{a}^{2}}({{l}^{2}}+{{m}^{2}})\]

    B)            \[{{(hl+km+n)}^{2}}=a({{l}^{2}}+{{m}^{2}})\]

    C)            \[{{(hl+km+n)}^{2}}={{a}^{2}}({{l}^{2}}+{{m}^{2}})\]

    D)            None of these

    Correct Answer: C

    Solution :

               According to the condition, \[a=\frac{hl+mk+n}{\sqrt{{{l}^{2}}+{{m}^{2}}}}\]                    \[\Rightarrow {{(hl+km+n)}^{2}}={{a}^{2}}({{l}^{2}}+{{m}^{2}})\].


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