JEE Main & Advanced Mathematics Circle and System of Circles Question Bank Tangent and normal to a circle

  • question_answer
    The line \[(x-a)\cos \alpha +(y-b)\]\[\sin \alpha =r\]will be a tangent to the circle \[{{(x-a)}^{2}}+{{(y-b)}^{2}}={{r}^{2}}\]

    A)            If \[\alpha ={{30}^{o}}\]    

    B)            If \[\alpha ={{60}^{o}}\]

    C)            For all values of \[\alpha \]     

    D)            None of these

    Correct Answer: C

    Solution :

               According to the condition of tangency                    \[r=\frac{a\cos \alpha +b\sin \alpha -(a\cos \alpha +b\sin \alpha )-r}{\sqrt{{{\cos }^{2}}\alpha +{{\sin }^{2}}\alpha }}\]                    \[\Rightarrow r=|-r|\ \Rightarrow r=r\].                    Therefore, it is a tangent to the circle for all values ofa.


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