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JEE Main & Advanced Mathematics Circle and System of Circles Question Bank Tangent and normal to a circle

  • question_answer
    The equation of the tangent to the circle \[{{x}^{2}}+{{y}^{2}}-2x-4y-4=0\] which is perpendicular to \[3x-4y-1=0\], is

    A)            \[4x+3y-5=0\]                        

    B)            \[4x+3y+25=0\]

    C)            \[4x-3y+5=0\]                        

    D)            \[4x+3y-25=0\]

    Correct Answer: D

    Solution :

               Tangent is of form\[4x+3y+c=0\]. From condition of tangency to the circle, we get\[c=-25\]. Hence equation is\[4x+3y-25=0\].


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