JEE Main & Advanced Mathematics Applications of Derivatives Question Bank Tangent and Normal

  • question_answer
    The points on the curve \[y=12x-{{x}^{3}}\]at which the gradient is zero are [MP PET 1999]

    A)            (0, 2), (2,16)

    B)            (0, ? 2), (2, ? 16)

    C)            (2, ?16), (? 2, 16)

    D)            (2, 16), (? 2, ? 16)

    Correct Answer: D

    Solution :

                       \[\frac{dy}{dx}=12-3{{x}^{2}}=0\Rightarrow x=\pm 2\]            Hence points are (2,16) and (?2, ?16).


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