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JEE Main & Advanced Mathematics Applications of Derivatives Question Bank Tangent and Normal

  • question_answer
    The slope of tangent to the curve\[x={{t}^{2}}+3t-8\], \[y=2{{t}^{2}}-2t-5\] at the point (2, ?1) is [MNR 1994]

    A)            \[\frac{22}{7}\]

    B)            \[\frac{6}{7}\]

    C)            ? 6 

    D)            None of these

    Correct Answer: B

    Solution :

                       \[t=2\]for the point (2,?1)                    \[\frac{dy}{dx}=\frac{4t-2}{2t+3}=\frac{6}{7}\]for \[t=2\].


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