A) 4, ? 14
B) 4, 14
C) ?4, 14
D) ?4, ?14
Correct Answer: A
Solution :
We have, \[{{y}^{2}}=5x-1\] ?..(i) At \[(1,-2)\]; \[\frac{dy}{dx}={{\left[ \frac{5}{2y} \right]}_{(1,\,-2)}}=\frac{-5}{4}\] \[\therefore \] Equation of normal at the point (1, ?2) is, \[[y-(-2)]\,\left[ \frac{-5}{4} \right]+x-1=0\] \[\therefore 4x-5y-14=0\] ??(ii) As the normal is of the form \[ax-5y+b=0\], comparing this with (ii), we get \[a=4\] and \[b=-14\].You need to login to perform this action.
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