A) \[2x+y+4=0\]
B) \[2x-y-12=0\]
C) \[2x+y-4=0\]
D) \[2x-y+4=0\]
Correct Answer: D
Solution :
\[{{x}^{2}}=-4y\]Þ\[2x=-4\frac{dy}{dx}\]Þ\[\frac{dy}{dx}=\frac{-x}{2}\]Þ\[{{\left( \frac{dy}{dx} \right)}_{(-4,\,-4)}}=2\]. We know that equation of tangent is, \[(y-{{y}_{1}})\,=\,{{\left( \frac{dy}{dx} \right)}_{({{x}_{1}},\,{{y}_{1}})}}(x-{{x}_{1}})\] Þ \[y+4=2(x+4)\] Þ \[2x-y+4=0\].You need to login to perform this action.
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