A) (2, 1)
B) (1, 2)
C) (3, 9)
D) (?2, 1)
Correct Answer: B
Solution :
\[y=2{{x}^{2}}-x+1\] Þ \[\frac{dy}{dx}=4x-1\]. We know that this equation gives the slope of tangent to the curve. Since this tangent is parallel to \[y=3x+9,\] therefore slope of the tangent is 3, so \[4x-1=3\] or \[x=1.\] Therefore \[y=2{{x}^{2}}-x+1=2-1+1=2.\] Thus the point \[(x,\,y)\] is (1, 2).You need to login to perform this action.
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