2. Questions Bank
  3. JEE Main & Advanced
  4. Mathematics
  5. Applications of Derivatives

JEE Main & Advanced Mathematics Applications of Derivatives Question Bank Tangent and Normal

  • question_answer
    The equation of the normal to the curve \[y=\sin \frac{\pi x}{2}\]at (1, 1) is                          [AMU 1999]

    A)            \[y=1\]

    B)            \[x=1\]

    C)            \[y=x\]

    D)            \[y-1=\frac{-2}{\pi }(x-1)\]

    Correct Answer: B

    Solution :

                       \[y=\sin \frac{\pi x}{2}\] Þ \[\frac{dy}{dx}=\frac{\pi }{2}\cos \frac{\pi }{2}x\]Þ \[{{\left( \frac{dy}{dx} \right)}_{(1,\,\,1)}}=0\]                    \ Equation of normal is \[y-1=\frac{1}{0}(x-1)\]                     Þ\[x=1\].


You need to login to perform this action.
You will be redirected in 3 sec spinner