A) 1
B) 2
C) 4
D) 8
Correct Answer: B
Solution :
\[500+50\sin \,2\theta =500+50\sin \theta \] \[\sin \,\,2\theta =\sin \theta \] Or \[\sin \,\,2\theta =\sin \theta =0\] \[2\sin \theta \cos \theta -\sin \theta =0\] Either \[\sin \theta =0\] giving \[\theta =0{}^\circ ,\]\[180{}^\circ ,\] \[360{}^\circ \] or \[\cos \theta =\frac{1}{2},\] giving \[\theta =60{}^\circ ,\] \[300{}^\circ \] \[\theta =0{}^\circ ,\] \[60{}^\circ ,\] \[180{}^\circ ,\] \[300{}^\circ \]= 4 times
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