question_answer

Given that

m = mass of the ball of the governor,

\[\omega \,\,=\] angular velocity of the governor and

g = accelerate due to gravity,

The height of Watt's governor is given by:

A) \[\frac{g}{2{{\omega }^{2}}}\]            

B) \[\frac{g}{{{\omega }^{2}}}\]

C) \[\frac{\sqrt{2g}}{{{\omega }^{2}}}\]              

D) \[\frac{g}{{{\omega }^{2}}}\]