A) \[110{}^\circ N\]
B) \[180{}^\circ N\]
C) \[210{}^\circ N\]
D) \[280{}^\circ N\]
Correct Answer: D
Solution :
Let \[t={{a}_{x}}+b\] \[400=a{{x}_{s}}+b\] \[100=a{{x}_{i}}+b\] \[a=\frac{300}{{{x}_{s}}-{{x}_{i}}},\] \[b=100-\frac{300{{x}_{i}}}{{{x}_{s}}-{{x}_{i}}}\] \[t{}^\circ N=\left( \frac{300}{{{x}_{s}}-{{x}_{i}}} \right)\,x+100-\frac{300{{x}_{i}}}{{{x}_{s}}-{{x}_{i}}}\] \[=\left( \frac{300}{{{x}_{s}}-{{x}_{i}}} \right)\,\,(x-{{x}_{i}})+100\] Also \[t{}^\circ C=\left( \frac{x-{{x}_{i}}}{{{x}_{s}}-{{x}_{i}}} \right)\times 100\] \[t{}^\circ N=3\,t{}^\circ C+100=3\times 60+100=280{}^\circ N\]
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