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Railways NTPC (Technical Ability) Thermodynamics Question Bank Thermodynamics

  • question_answer
      The thermal efficiency of the Carnot engine is 0.5. If the engine is operated as refrigerator, what is the COP of the refrigerator?                     

    A) 0.5                               

    B) 1.0             

    C) 2.0                               

    D) 25

    Correct Answer: B

    Solution :

    \[{{\eta }_{Carnot}}1-\frac{{{T}_{2}}}{{{T}_{1}}}=0.5\] \[\frac{{{T}_{2}}}{{{T}_{1}}}=0.5\] \[{{(COP)}_{\text{Ref}}}=\frac{{{T}_{2}}}{{{T}_{1}}-{{T}_{2}}}=\frac{1}{\frac{{{T}_{1}}}{{{T}_{2}}}-1}=\frac{1}{2-1}=1.0\]


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