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Railways NTPC (Technical Ability) Thermodynamics Question Bank Thermodynamics

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    What is the molecular weight (approximate) for the gas whose specific heats are as follows? \[{{c}_{p}}=1.967\,\,kJ/kg\,\,K\,;\]          \[{{c}_{v}}=1.507\,\,kJ/kg\,\,K\,\,\]

    A) 17                                

    B) 18

    C) 19                                

    D) 20

    Correct Answer: B

    Solution :

    \[R={{c}_{p}}-{{c}_{v}}=1.967-1.507=0.46\] \[Molecular\,\,weight,\,\,\,M=\frac{{{R}_{u}}}{R}=\frac{8.314}{0.46}=18\]


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