A) \[-\,\,8\]
B) zero
C) 10
D) \[-\,\,10\]
Correct Answer: C
Solution :
\[\delta Q=dU+\delta W\] \[\delta {{Q}_{1}}=d{{U}_{1}}+\delta {{W}_{1}}\] \[0=d{{U}_{1}}+\delta {{W}_{1}}\] \[Similarly\,\,\,8=d{{U}_{2}}+\delta {{W}_{2}}\] \[6=d{{U}_{3}}+\delta {{W}_{3}}-4=d{{U}_{4}}+\delta {{W}_{4}}\] \[0+8+6-4=\left( d{{U}_{1}}+d{{U}_{2}}+d{{U}_{3}}+d{{U}_{4}} \right)\] \[+\left( \delta {{W}_{1}}+\delta {{W}_{2}}+\delta {{W}_{3}}+\delta {{W}_{4}} \right)\] \[10=\sum{dU+0}\] \[\therefore \,\,\,\,\sum{dU=10\,\,units.}\]
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