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Railways NTPC (Technical Ability) Thermodynamics Question Bank Thermodynamics

  • question_answer
    In an adiabatic process 6000 J of work is performed on a system. In the non-adiabatic process by which the system returns to its original state, 1000 J of heat is added to the system. What is the work done during non-adiabatic process?

    A) \[+\,\,7000\,\,J\]            

    B) \[-\,\,7000\,\,J\]

    C) \[+\,\,5000\,\,J\]            

    D) \[-\,\,5000\,\,J\]

    Correct Answer: A

    Solution :

    \[W=-\,\,600\,J,\] \[Q=+1000\,J,\] In an adiabatic process, Q = 0 \[{{Q}_{1\,-\,2}}={{W}_{1\,-\,2}}+{{U}_{1\,-\,2}}\]             \[0=-\,\,6000+{{U}_{1\,-\,2}}\] \[{{U}_{1\,-\,2}}\,\,=\,\,6000\,\,J,\] \[{{U}_{2\,-\,1}}=-\,\,6000\,\,J\] In a non-adiabatic process, \[{{Q}_{2\,-\,1}}={{W}_{2\,-\,1}}+{{U}_{2\,-\,1}}\] \[1000\,\,=\,\,{{W}_{2\,-\,1}}\,-\,\,6000\] \[{{W}_{2\,-\,1}}=+7000\,J\]


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