Railways NTPC (Technical Ability) Thermodynamics Question Bank Thermodynamics

  • question_answer
    Heat flows between two reservoirs having temperatures 1000 K and 500 K, respectively. If the entropy change of the cold reservoir is 10 kJ/K, then what is the entropy change for the hot reservoir?

    A) \[-\,\,10\,\,kJ/K\]             

    B) \[-\,\,5\,\,kJ/K\]

    C) \[5\,\,kJ/K\]                   

    D) \[10\,\,kJ/K\]

    Correct Answer: D

    Solution :

    \[\frac{{{Q}_{1}}}{{{T}_{1}}}=\frac{{{Q}_{2}}}{{{T}_{2}}}\] \[\frac{{{Q}_{1}}}{1000}=\frac{{{Q}_{2}}}{5000}\] \[{{Q}_{1}}=2{{Q}_{2}}\] Now \[\frac{{{Q}_{2}}}{{{T}_{2}}}=10,\] \[{{Q}_{2}}=500\times 10=5000\,\,kJ\] \[\therefore \,\,\,{{Q}_{1}}=2\times 5000=10,000\,\,kJ\] \[\Delta \,{{S}_{1}}\,\,=\,\,\frac{{{Q}_{1}}}{{{T}_{1}}}\,\,=\,\,\frac{10,000}{1,000}\,\,=\,\,10\,\,\text{kJ/K}\]


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