A) 0 and 150 J/K
B) 150 J/K and 0
C) 300 J/K and 0
D) 0 and 300 J/K
Correct Answer: A
Solution :
\[Q={{I}^{2}}\,\,Rt={{\left( 0.5 \right)}^{2}}\times 100\times 30\times 60\times {{10}^{-\,3}}=45\,\,kJ\] \[{{\left( \Delta \,S \right)}_{universe}}=\frac{Q}{T}=\frac{45\times 1000}{300}=150\,\,\text{J/K}\] \[{{\left( \Delta \,S \right)}_{resistor}}=0\]
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