question_answer

If 6 men and 8 boys can do a piece of work in 10 days and 26 men and 48 boys can do the same work in 2 days, the time taken by 15 men and 20 boys to do the same type of work will be

A) 6 days             

B)          4 days

C) 8 days             

D)          7 days.

Correct Answer: B

Solution :

    Given \[(6M+6B)\times \,10=(26\,M+48\,B)\times 2\] \[\Rightarrow \,60\,M+80\,B=52\,M\,+96\,B\] \[\Rightarrow \,8\,M=16\,B\] \[\Rightarrow \,1\,M\,=2\,B\] \[\therefore \,\,15\,M+20B=30B+20B=50B\] \[6\,M+8B=12B+8B=20B\] Now \[\therefore \]    \[x=\frac{20\times 10}{50}=4\] days