A) 2.047 s
B) 1.047 s
C) 3.047 s
D) 0.047 s
Correct Answer: B
Solution :
Length of the line = Distance between extreme positions of oscillation = 4 cm So, Amplitude \[a=2\,cm.\] also \[{{v}_{max}}=12\,cm/s.\] \[\because {{v}_{\max }}=\omega a=\frac{2\,\pi }{T}a\] \[\Rightarrow T=\frac{2\,\pi a}{{{v}_{max}}}\]\[=\frac{2\times 3.14\times 2}{12}\]\[=1.047\,\sec \]
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