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Railways NTPC (Technical Ability) Tool Engineering Question Bank Tool Engineering

  • question_answer
          For A \[\text{M/M/I}:\,\infty \,\text{/FCFS}\] queue, the mean array rate is equal to 10 per hour and the mean service rate is 15 per hour The expected queue length is:        

    A) 1.33                             

    B) 1.53           

    C) 2.75                 

    D) 3.20 

    Correct Answer: A

    Solution :

    \[\lambda =10,\] \[\mu =15,\] \[\rho =\frac{\lambda }{\mu }=\frac{10}{15}=\frac{2}{3}\] Expected queue length \[=\frac{{{\rho }^{2}}}{1-\rho }=\frac{(\text{4/9})}{(1-\text{2/3})}=1.33\]


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