A) 1.33
B) 1.53
C) 2.75
D) 3.20
Correct Answer: A
Solution :
\[\lambda =10,\] \[\mu =15,\] \[\rho =\frac{\lambda }{\mu }=\frac{10}{15}=\frac{2}{3}\] Expected queue length \[=\frac{{{\rho }^{2}}}{1-\rho }=\frac{(\text{4/9})}{(1-\text{2/3})}=1.33\]You need to login to perform this action.
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