JEE Main & Advanced Physics Atomic Physics Question Bank Topic Test - Atomic Physics

  • question_answer
    The first line in the Lyman series has wavelength l. The wavelength of the first line in Balmer series is         

    A) \[\frac{2}{9}\lambda \]

    B) \[\frac{9}{2}\lambda \]

    C) \[\frac{5}{27}\lambda \]

    D) \[\frac{27}{5}\lambda \]

    Correct Answer: D

    Solution :

    [d] For first line in Lyman series \[{{\lambda }_{{{L}_{1}}}}=\frac{4}{3\ R}\]
    For first line in Balmer series \[{{\lambda }_{{{B}_{1}}}}=\frac{36}{5\ R}\]
    From equation (i) and (ii)
    \[\frac{{{\lambda }_{{{B}_{1}}}}}{{{\lambda }_{{{L}_{1}}}}}=\frac{27}{5}\Rightarrow {{\lambda }_{{{B}_{1}}}}=\frac{27}{5}{{\lambda }_{{{L}_{1}}}}\Rightarrow {{\lambda }_{{{B}_{1}}}}=\frac{27}{5}\lambda \]
     


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