JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Topic Test - Chemical Equilibrium (6-5-21)

15 moles of \[{{H}_{2}}\] and 5.2 moles of \[{{I}_{2}}\] are mixed and allowed to attain equilibrium at \[{{500}^{o}}C\]. At equilibrium, the concentration of \[HI\] is found to be 10 moles. The equilbrium constant for the formation of \[HI\] is

A) 50

B) 15

C) 100

D) 25

Correct Answer: A

Solution :

[a] \[{{H}_{2}}\] + \[{{I}_{2}}\] \[\rightleftharpoons \] \[2HI\]

15 5.2 0

(155) (5.25) 10

\[{{K}_{C}}=\frac{{{[HI]}^{2}}}{[{{H}_{2}}][{{I}_{2}}]}=\frac{10\times 10}{10\times 0.2}=50\]