A) \[{{K}_{P}}=({{P}_{CaO}}+{{P}_{C{{O}_{2}}}}/{{P}_{CaC{{O}_{3}}}})\]
B) \[{{K}_{P}}={{P}_{C{{O}_{2}}}}\]
C) \[{{K}_{P}}\times ({{P}_{CaO}}\times {{P}_{C{{O}_{2}}}}).{{P}_{CaC{{O}_{3}}}}\]
D) \[\frac{{{K}_{p}}[CaO][C{{O}_{2}}]}{[CaC{{O}_{3}}]}\]
Correct Answer: B
Solution :
[b] \[CaC{{O}_{3(s)}}\]\[\rightleftharpoons \] \[Ca{{O}_{(s)}}+C{{O}_{2(g)}}\] |
\[{{K}_{p}}={{P}_{C{{O}_{2}}}}\] |
Solid molecule does not have partial pressure so in calculation of \[{{K}_{p}}\]only \[{{P}_{C{{O}_{2}}}}\]is applicable. |
You need to login to perform this action.
You will be redirected in
3 sec