A) 50
B) 5
C) 0.2
D) 0.02
Correct Answer: D
Solution :
[d] \[{{K}_{{{c}_{1}}}}\] for \[{{H}_{2}}+{{I}_{2}}\]\[\rightleftharpoons \] 2HI is 50 |
\[{{K}_{{{c}_{2}}}}\] for 2HI \[\rightleftharpoons \]\[{{H}_{2}}+{{I}_{2}}\] |
\[{{K}_{{{c}_{2}}}}=\frac{1}{{{K}_{{{c}_{1}}}}}=\frac{1}{50}=0.02\] |
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