A) +1.82 V
B) +1.99 V
C) +1.608 V
D) +1.054 V
Correct Answer: D
Solution :
| [d] \[{{E}_{C{{r}_{2}}O_{7}^{2-}/C{{r}^{3+}}}}\] |
| \[=E_{C{{r}_{2}}O_{7}^{2-}/C{{r}^{3+}}}^{o}-\frac{0.0591}{6}\log \frac{{{[C{{r}^{3+}}]}^{2}}}{[C{{r}_{2}}O_{7}^{2-}]{{[{{H}^{+}}]}^{14}}}\] |
| \[=1.33-\frac{0.0591}{6}\log \frac{1}{{{(0.01)}^{14}}}\] |
| \[=1.0542\text{ }V\] |
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