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JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Topic Test - Electrochemistry

  • question_answer
    Match List I with List II and select the correct answer using the code given below the lists:
    List I List II
    \[Zn|Z{{n}^{2+}}(0.01M)|\,\]\[|Z{{n}^{2+}}(0.1M)|Zn\] (p) primary cell
    1 Coulomb (q) Secondary cell
    Dry Cell (r) \[6.24\times {{10}^{18}}\]electrons
    Lead storage cell (s) Concentration cell

    A) A-s,       B-r,       C-p,      D-q                

    B) A-p,      B-q,      C-r,       D-s

    C) A-q,      B-r,       C-s,       D-p                

    D) A-s,       B-p,      C-q,      D-r

    Correct Answer: A

    Solution :

    [a]
    [a] is concentration cell.
    [b] \[1{{e}^{-}}=1.6\times {{10}^{-19}}\] colulomb
    1 coulomb \[=\frac{{{10}^{19}}}{1.6}=6.24\times {{10}^{18}}\]
    [c] Dry cell is a primary cell.
    [d] Lead storage cell is secondary cell.


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