A) 3, 1 and 2
B) 1, 3 and 2
C) 3, 1 and 3
D) 2, 3 and 2
Correct Answer: B
Solution :
| [b] Eq. of A = Eq. of B = Eq. of C |
| \[\frac{2.1}{7/{{n}_{1}}}=\frac{2.7}{27/{{n}_{2}}}=\frac{7.2}{48/{{n}_{3}}}\] |
| \[0.3{{n}_{1}}=0.1{{n}_{2}}=0.15{{n}_{3}}\] |
| \[\therefore \] \[{{n}_{1}}=\frac{{{n}_{2}}}{3}=\frac{{{n}_{3}}}{2}=\left( {{n}_{1}},{{n}_{2}},{{n}_{3}} \right)\] are integers. |
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