Car is accelerating with acceleration = 20 m/s2. A box of mass m = 10 kg that is placed inside the car it is put in contact with the vertical wall of car as shown. The friction coefficient between the box and the wall is \[\mu =0.6\]. |
A) The acceleration of the box will be \[10\,m/{{\sec }^{2}}\]
B) The friction force acting on the box will be 100 N
C) The contact force between the vertical wall and the box will be 100 N
D) None of these
Correct Answer: B
Solution :
The breaking force is insufficient, so the block will not slide. |
So friction force = 100 N |
and acceleration will be \[20\,m/{{\sec }^{2}}\]only |
Net contact force on the block |
\[=\sqrt{{{\left( 200 \right)}^{2}}+{{\left( 100 \right)}^{2}}}\,=\,100\sqrt{5\,}\,N\] |
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